BITSAT 2013 Paper

∴ 4i1+2(i1+i2) - 3 + 4 i−1 = 16V ... (i)
Using Kirchhoff’s second law in the closed loop we have
9 - i2−2(i1+i2) = 0 ... (ii)
Solving equations (i) and (ii), we get
i1 = 1.5A and i2 = 2 A
∴ current through 2W resistor = 2 + 1.5 = 3.5 A.