BITSAT 2013 Paper

Section: Physics

Question : 2 of 150

Marks: +1, -0

A man runs at a speed of 4 m/s to overtake a standing bus. When he is 6 m behind the door at t = 0, the bus moves forward and continuous with a constant acceleration of 1.2 m/s2. The man reaches the door in time t. Then,

4 t = 6 + 0.6 t2
1.2 t2 = 4 t
4 t2 = 1.2 t
6 + 4 t = 0.2 t2

Validate

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