BITSAT 2011 Paper

We shall first consider values of θ between 0 and 2π sin θ =

1

2

= - sin

π

6

= sin (π+

π

6

)
or sin (2π – π/6)
∴ θ = 7π/6 ; 11π/6
tan θ = 1/√3 = tan (π/6) or tan (π + π/6)
∴ θ = π/6 , 7π/6
The value of θ which satisfies both the equations is 7π/6
Hence the general value of θ is 2nπ + 7π/6 where n ∊ I