If \C=2 \cos \\theta, then the value of the determinant to \table \\Delta=\C,1,0;1,\C,1;6,1,\C is

Correct Answer is : 8cos3θ−4cosθ+6

{2 \sin ^{2} 2 \\theta}/{\sin \\theta}

8 \cos ^{3} \\theta-4 \cos \\theta+6

\frac{2 \sin 2 \\theta}{\sin \\theta}

8 \cos ^{3} \\theta+4 \cos \\theta+6

BITSAT 2007 Solved Question Paper

Section: Mathematics

Question : 4 of 150

Marks: +1, -0

If C=2‌cos‌θ, then the value of the determinant to

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