The sum to n terms of the infinite series 1 .3^{2}+2 .5^{2}+3 .7^{2}+ ...\infty is

Correct Answer is : n6(n+1)(6n2+14n+7)

\frac{n}{6}(n+1)(6 n^{2}+14 n+7)

BITSAT 2007 Solved Question Paper

Section: Mathematics

Question : 33 of 150

Marks: +1, -0

The sum to n terms of the infinite series 1.32+2.52+3.72+ ...∞ is

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