BITSAT 2006 Solved Question Paper

Section: Mathematics

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Question : 3 of 150

Marks: +1, -0

The ends of the latus rectum of the conic x2+10x−16y+25=0 are :

(3,−4),(13,4)
(−3,−4),(13,−4)
(3,4),(−13,4)
(5,−8),(−5,8)

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