BITSAT 2006 Solved Question Paper

Section: Mathematics

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Question : 26 of 150

Marks: +1, -0

The equation to the circle with centre (2,1) and touching the line 3x+4y=5 is :

x2+y2−4x−2y+5=0
x2+y2−4x−2y−5=0
x2+y2−4x−2y+4=0
x2+y2−4x−2y−4=0

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