BITSAT 2006 Solved Question Paper

Let the points be A(3,−4) and B(5,2) and mid point of AB=(4,−1).
It is given that the bisecting line intercept the co-ordinate axes in the ratio 2:1.
∴ Point of co-ordinate axes are (2k,0) and (0,k). The equation of line passing through the above point is
y−0=

k−0

0−2k

(x−2k)
ory=−

1

2

(x−2k) ...(i)
Since, it is passing through the mid point of AB i. e., (4,−1)
⇒−1=−

1

2

(4−2k)
⇒2=4−2k
⇒ k = 1
Putting the value of k in Eq. (i), we get
y=−

1

2

(x−2)
⇒x+2y=2