The standard reduction potential of the reation, {\H}_{2} {\O}+\e^{-} \\to\frac{1}{2} {\H}_{2}+{\OH} at 298 {\K} is:

Correct Answer is : E°=RTFlnKw

E^\circ=\frac{R T}{F} \ln K_{w}

E^\circ=-\frac{R T}{F} \ln [P_{{H}_{2}}]^{1 \/ 2}[{OH}^{-}]

E^\circ=-\frac{R T}{F} \ln {[P_{{H}_{2}}]^{1 \/ 2}}/{[{H}^{+}]}

E^\circ=-\frac{R T}{F} \ln K_{w}

BITSAT 2005 Solved Question Paper

Section: Chemistry

Question : 99 of 150

Marks: +1, -0

The standard reduction potential of the reation, H2O+e−→

H2+OH at 298K is:

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