For the reaction (at 1240 { \K} and 1 { \atm}.) {\CaCO}_{3}(s) \\to{\CaO}(s)+{\CO}_{2}(g) \\Delta\H=176 {\kJ} \/ {\mol} ; \\Delta\E will be :

BITSAT 2005 Solved Question Paper

Section: Chemistry

Question : 97 of 150

Marks: +1, -0

For the reaction (at 1240 K and 1 ‌atm.)
CaCO3(s)→CaO(s)+CO2(g)
ΔH=176‌kJ∕mol;ΔE will be :

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