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Question : 3 of 150
Marks:
+1,
-0
Solution:
Given that
=+2−3 and
=3−+2 +=+2−3+3−+2 =4+− and
−=(+2−3)−(3−+2) =−2+3−5 Let
θ be the angle between
+ and
− cos‌θ= =| (4+−).(−2+3−5) |
| |4+−||−2+3−5| |
=| −8+3+5 |
| √16+1+1√4+9+25 |
=0 ⇒θ=90°
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