BA LLB Banaras Hindu University 2017 Solved Paper

Question : 97 of 170

Marks: +1, -0

A B C × D E E D=A B C A B C, \;\;

where

A, B, C, D

and

E

are different digits, what are the values of

D

and

E ?

Solution:

\ABC ×\DEED=\ABCABC

Firstly

\ABC

is must be multiply with 1 to get the same and after then it is multiplied with 0 , so that the value don't get changed.

∴ \;\; D=1

and

E=0

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