BA LLB Banaras Hindu University 2017 Solved Paper

Question : 125 of 170

Marks: +1, -0

Let the least number of six digits which when divided by

4,6,10,15

leaves in each case same remainder 2 be

{N}

. The sum of digits in

{N}

Solution:

\because

LCM of

4,6,10,15=60

60)100000(1666

\;\;60

\;───

\;\;\;\;\;\;400

\;\;\;360

\;────

\;\;\;400

\;\;\;360

\;─────

\;\;400

\;\;360

\;─────

40

That number

=100000+(60-40)+2

{N}=100022

∴

Required value

=5

Go to Question:

Prev Question

Next Question