A horizontal conducting wire of length 20 {cm} carries as current of 2 {A}. If the mass of the wire is 8 \times 10^{-5} {kg}, what will be the uniform magnetic induction required to support weight of the wire? [take g=10 {m} \/ {s}^{2}, \sin 90^{\circ}=\cos 0^{\circ}=1]

Auxiliary Nurse Midwife Exam 2020 Solved Paper

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A horizontal conducting wire of length 20 cm carries as current of 2A. If the mass of the wire is 8×10−5kg, what will be the uniform magnetic induction required to support weight of the wire? [take g=10m∕s2,sin‌90∘=cos‌0∘=1]

0.5×10−3T
10−3T
2.5×10−3T
2×10−3T

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