AP ICET 2019 Shift 2 Paper

The speed ratios of the person i.e, (present speed) ${\mathit{V}}_{\mathrm{p}}$ : (usual speed ) ${\mathit{V}}_{\mathrm{u}}=3:4$
The time ratios of the person ${\mathit{T}}_{\mathit{p}}:{\mathit{T}}_{\mathit{u}}=4:3$
$\Rightarrow 4\mathit{p}-3\mathit{p}=15$ minutes
⇒ p = 15 minutes
Usual time taken by the person $=3\mathit{p}=3\times 15$
= 45 minutes $=\frac{3}{4}$ hours