AP ICET 2019 Shift 2 Paper

Question : 84 of 200

Marks: +1, -0

The smallest positive integer, when increased by 9, is exactly divisible by 3, 4, 10, 15, 24 is

Solution:

The LCM of (3 , 4 , 10 , 15 , 24 ) is 120
The required answer is

120-9 = 111.

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