AP ICET 2019 Shift 2 Paper

Question : 82 of 200

Marks: +1, -0

Sum of all the two-digit numbers that are divisible by 4 is

Solution:

The number of two-digit numbers that are divisible by

4={96-12}/4+1=22

The sum of all the two – digit numbers that are divisible by

4={22}/{2}(96+12)=11×108=1188

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