AP ICET 2019 Shift 2 Paper

Question : 77 of 200

Marks: +1, -0

If 3” divides

(72)^9. (24)^7 .(48)^{11}

, then the largest integral value of is

Solution:

⇒(72)^{9} ×(24)^{7} ×(48)^{11}=(3^{2}×8)^{9} ×(3 × 8)^{7}×

(3×16)^{11}=(3^{18} × 8^{9}) ×(3^{7} × 8^{7}) ×(3^{11} × 16^{11})

=3^{36} × 8^{16} × 16^{11}

∴ The maximum integral value of n is 36

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