AP ICET 2019 Shift 2 Paper

Question : 144 of 200

Marks: +1, -0

The mean of the numbers a, b, S, 5, 10 is 6 and their variance is 6.80. Then the difference between a and b is

Solution:

\;{a+b+8+5+10}/{5}=6 ⇒ a+b=7

,→(1)

\;{(6-a)^{2}+(6-b)^{2}+(8-6)^{2}+(5-6)^{2}+(10-6)^{2}}/{5}=6.80

=(6-a)^{2}+(6-b)^{2}=34-4-1-16

(6-a)^{2}+(6-b)^{2}=13

→ (2)
Solving (1) and (2) a = 4 and b = 3

∴a-b=1

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