AP ICET 2019 Shift 2 Paper

Question : 137 of 200

Marks: +1, -0

The perimeter (in cms) of a Rhombus whose diagonals are 9 cm and 12 cm is

Solution:

Side(S)

=√{(\;{d_{1}}/{2})^{2}+(\;{d_{2}}/{2})^{2}}

√{\;{81}/{4}+36}=√{\;{225}/{4}}=\;{15}/{2}

Perimeter

= 4S = 30

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