d/{dx}(\tan^{-1} (\frac{1+tanx}{1-tanx})) =

AP ICET 2019 Shift 2 Paper

Question : 135 of 200

Marks: +1, -0

d/{dx}(tan^{-1} ({1+tanx}/{1-tanx}))

Solution:

\;{d}/{d}\tan^{-1}(\tan (\;{π}/{4}+x))

{d}/{d x}({π}/{4}+x)=1

Go to Question:

Prev Question

Next Question