AP ICET 2019 Shift 2 Paper

Question : 128 of 200

Marks: +1, -0

The sum of the first 25 terms in the progression

2,5/2,3

, .... is

Solution:

S_{25}=\;{25}/{2}[2(2)+24 ×{1}/{2}]

=25 × 8=200

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