AP ICET 2019 Shift 2 Paper

Question : 121 of 200

Marks: +1, -0

If the angles of elevation of the top of a tower from the top and front of a pole of height 15m are 30° and 60° respectively, then the height of the tower (in meters) is

23
$22 1/2$
22
$24 1/2$

Validate

Solution:

In Δ ACD
AC

=h/√3

In ΔBED,

\tan30°={DE}/{BE}

\;{1}/{√{3}}=\;{h-15}/{{h}/{√{3}}}

⇒ h =3 h -45 ⇒ h =22\;{1{/}2}

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