AP ICET 2019 Shift 2 Paper

Question : 117 of 200

Marks: +1, -0

If the straight lines 5x + 3y + 7 = 0 and ax - 7y + 8 = 0 are perpendicular, then the value of a is

Solution:

Product of slopes is –1

\;{-5}/{3} × \;{a}/{7}=-1 ⇒ a=\;{21}/{5}

Go to Question:

Prev Question

Next Question