AP ICET 2019 Shift 2 Paper

The length of the rectangle is equal to the circumference of the cylindrical base and the breadth of the rectangle is height of the cylinder
$\Rightarrow 2\mathit{\pi }\mathit{r}=20\mathit{m}$
$\Rightarrow \mathit{r}=\frac{10}{\mathit{\pi }}\mathit{m}$ and $\mathit{h}=12\mathit{m}$
The volume of the cylinder $=\mathit{\pi }\times \frac{10}{\mathit{\pi }}\times \frac{10}{\mathit{\pi }}\times 12=\frac{1200}{\mathit{\pi }}{\mathit{m}}^3$