AP ICET 2019 Shift 1 Paper

Question : 86 of 200

Marks: +1, -0

(1-1/7)(1-1/8)(1-1/9)(1-1/{10})

....

(1-1/{51})

Solution:

(1-{1}/{7})(1-{1}/{8})(1-{1}/{9}).....(1-{1}/{51})

=({6}/{7})({7}/{8})({8}/{9}).....({50}/{51})

In this result the denominator of the first fraction and the numerator of the second fraction and so on are getting cancelled.
Result = 6/51 = 2/17.

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