AP ICET 2019 Shift 1 Paper

Question : 150 of 200

Marks: +1, -0

A and B arc two sets such that n(A) = 3 and n(B) = 2. If a relation from A to B is selected at random, then the probability that the relation will be a function is

$1/2$
$1/4$
$3/8$
$1/8$

Validate

Solution:

Given n (A) = 3 and n (B) = 2 The number of relations from A to B is

2^{3×2}=2^6

The number of functions possible from A to B is

(n(B))^{n(A)}=2^3=8

∴ The required probability

=8/2^6=1/8

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