AP ICET 2019 Shift 1 Paper

Question : 138 of 200

Marks: +1, -0

A, B and C are three points on the circumference of a circle with centre O. If in Δ ABC ∠B = 60° and ∠C = 70° then ∠BOC =

Solution:

In ΔABC

∠A=180-(∠B+∠C)

∠A=50°

⇒∠BOC=2∠A=100°

(∵ Angle at the Centre is double the angle at a point on the circle)

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