AP ICET 2019 Shift 1 Paper

Question : 127 of 200

Marks: +1, -0

Set X contains 10 consecutive integers. Sum of the 5 least numbers of the set is 265. The sum of the four greatest numbers of that set is

Solution:

Let the 10 numbers of the set be

x, x + 1, x + 2, x+ 3, x + 4, x + 5,.....,x + 9

.Sum of the first five (least five) numbers is

x + x+ 1 + x + 2 + x + 3 + x + 4 = 265

5x = 255

x = 51

Sum of the 4 greatest numbers is

x + 6 + x + 7 +x + 8 + x + 9

= 4x + 30 = 234

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