\sin^{2}60^{\circ}+\cos^{2}225^{\circ}+\tan^{2}210^{\circ}+\cot^{2}240^{\circ}=

AP ICET 2018 Afternoon Question Paper

Question : 118 of 200

Marks: +1, -0

\sin^{2}60^{∘}+\cos^{2}225^{∘}+\tan^{2}210^{∘}+\cot^{2}240^{∘}=

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