\frac{37}{50}, \frac{26}{37}, \frac{17}{26},\text{__________},\frac{1}{2}

AP ICET 2017 Shift 2 Paper

Question : 39 of 200

Marks: +1, -0

\;\;{37}/{50},\;\;{26}/{37},\;\;{17}/{26},\text "__________",{1}/{2}

Solution:

{37}/{50},

\;\;{26}/{37},

{17}/{26}

{1}/{2}

{6^{2}+1}/{7^{2}+1},{5^{2}+1}/{6^{2}+1},{4^{2}+1}/{5^{2}+1},\;\;{?}\;\;1/{3^{2}+1}

?=\;\;{3^{2}+1}/{4^{2}+1}=\;\;{10}/{17}

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