AP ICET 2017 Shift 2 Paper

Total number of outcomes $=62=36$
Favourable outcomes : (1, 1), ← 1 way
(1, 2),(1, 4),(1, 6),(2, 3),(2, 5),(3, 4),(4, 7), in 2 ways each.
∴ Number of favourable outcomes $=1+14=15$
∴ Required probability $=\frac{15}{36}$