Let ℕ be the set of all natural numbers and f:\mathbb{N}\to\mathbb{N} be defined by f(n)=r,where r is the remainder when n is divided by 17 for any n∊\mathbb{N}.Then \{n\in{N}:f(n)=3\}=

Correct Answer is : {17k+3:k=0,1,2,3,......}

\{17k+3:k=0,\pm1,\pm2,\pm3,.......\}

AP ICET 2017 Shift 2 Paper

Question : 115 of 200

Marks: +1, -0

Let ℕ be the set of all natural numbers and

f : ℕ \to ℕ

be defined by

f(n)=r

,where r is the remainder when n is divided by 17 for any

n∊ℕ

.Then

\{n∈{N}:f(n)=3\}=

Solution:

Given : f (n) = r where r is the remainder when n is divided by 17 for any n ∈N.
Divisor = 17
Remainder = 3
Dividend = Divisor × quotient + Remainder

∴\{n∈N:f(n)=3\}=\{17k+3:k=0,1,2,3,...\}

Go to Question:

Prev Question

Next Question