AP ICET 2017 Shift 2 Paper

Question : 108 of 200

Marks: +1, -0

The number of revolutions made by a wheel of 42 cms diameter in covering a distance of 1.32 kms is (Take

π=22/7

)

Solution:

Required number of revolutions

={{D}}/{2πr}={1.32×10^{5}}/{2×\;\;{22}/{7}×21}=1000

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