AP ICET 2017 Shift 1 Paper

© examsiri.com

Question : 88 of 200

Marks: +1, -0

If

a_1,a_2,a_3

and

a_4

is the decreasing order of the elements in

\{\;\;{2}/{7},\;\;{7}/{15},\;\;{5}/{8},\;\;{9}/{23}\}

then

a_1-a_4=

5/8
17/26
19/56
2/7

Solution:

{2}/{7}=0.286,{7}/{15}=0.467,{5}/{8}=0.625,{9}/{23}=0.391

⇒a_{1}={5}/{8}

and

a_{4}={2}/{7}

∴a_{1}-a_{4}={5}/{8}-{2}/{7}={35-16}/{56}={19}/{36}

© examsiri.com

Go to Question:

Prev Question

Next Question