(1-\frac{1}{5})(1-\frac{1}{6})(1\frac{1}{7}).... . ....(1-\frac{1}{200})=

AP ICET 2017 Shift 1 Paper

Question : 86 of 200

Marks: +1, -0

(1-{1}/{5})(1-{1}/{6})(1{1}/{7}).... . ....(1-{1}/{200})=

Solution:

(1-{1}/{5})(1-{1}/{6})(1-{1}/{7})...(1-{1}/{200})

={4}/{5}×{5}/{6}×{6}/{7}×. . .{199}/{200}={4}/{200}={1}/{50}=0.02

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