For a\geq4,\sqrt{3(a-1)+2\sqrt{2a^{2}-7a-4}}=

AP ICET 2017 Shift 1 Paper

Question : 81 of 200

Marks: +1, -0

For

a≥4,√{3(a-1)+2√{2a^{2}-7a-4}}=

Solution:

√{3(a-1)+2√{2a^{2}-7a-4}}

=√{3(a-1)+2√{2a^{2}+a-8a-4}}

=√{3(a-1)+2√{a(2a+1)-4(2a+1)}}

=√{3(a-1)+2√{(2a+1)(a-4)}}

=√{3a-3+2√{2a+1}⋅√{a-4}}

=√{(√{2a+1})^{2}+(√{a-4})^{2}+2√{2a+1}-√{a-4}}

=√{(√{2a+1}+√{a-4})^{2}}=√{2a+1}+√{a-4}

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