E↓F=(E+F)+(E-F)^{2};E↑F=(E+F)^{2}-(E-F)^{2}\Rightarrow(1+2)↓(2+3)=

AP ICET 2017 Shift 1 Paper

Question : 75 of 200

Marks: +1, -0

E↓F=(E+F)+(E-F)^{2};E↑F=(E+F)^{2}-(E-F)^{2}⇒(1+2)↓(2+3)=

Solution:

1↓2=(1+2)+(1–2)^2=3+1=4

2↑3=(2+3)^2–(2–3)^2=25–1=24

∴(1↓2)↓(2↑3)=4↓24=(4+24)+(4–24)^2

=28+400=428

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