AP ICET 2017 Shift 1 Paper

Question : 21 of 200

Marks: +1, -0

4 : 80 : : 5 : _______

Solution:

\;4

\;\;\;80

\;\;\;\5

: ?

\;\;\;\;\;\;\;↓

\;\;↓

\;\;\;4^2×(4+1)

\;\;\;\;\;5^2×(5+1)

∴?=5^2×(5+1)=25×6=150

Go to Question:

Prev Question

Next Question