AP ICET 2017 Shift 1 Paper

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Question : 132 of 200

Marks: +1, -0

If

α

is an integer

A=[\tableα^2,5;5,-α]

and

|A|^10=1024

then

α

$-2$
$2$
$-3$
$3$

Solution:

1024=2^10

⇒|A|^10=1024=2^10⇒|A|=2

|\tableα^2,5;5,-α|=2

⇒-α^3-25=2

⇒α^3=-27=(-3)^3

⇒α=-3

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