AP ICET 2017 Shift 1 Paper

Question : 129 of 200

Marks: +1, -0

If the common ratio of a geometric progression is

3/7

and its sum to infinite terms is 133 then the first term of the geometric progression is

Solution:

S_∞=a/{1-r}

⇒133=a/{1-3/7}⇒133=7/4a

⇒a=133×4/7=19×4

∴a=76

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