\frac{6}{a}+ \frac{15}{b}=8, \frac{10}{a}- \frac{9}{b}=2\Rightarrowa^{2}+b^{2}=

AP ICET 2017 Shift 1 Paper

Question : 126 of 200

Marks: +1, -0

\;\;{6}/{a}+\;\;{15}/{b}=8,\;\;{10}/{a}-\;\;{9}/{b}=2⇒a^{2}+b^{2}=

Solution:

6/a+15/b=8]×3

10/a-9/b=2]×5

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Add

68/a=34⇒a=2

Then

9/b=10/2-2=3⇒b=3

∴a^2+b^2=2^2+3^2=13

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