AP ICET 2016 Paper

Question : 91 of 200

Marks: +1, -0

0 < x < 19

and

14x≡6(\mod19)

, then x =

Solution:

Given : 0 ≤ x < 19 and 14x ≡ 6 (mod 19)

⇒14x–6

is divisible by 19
Among the given options, x = 14 satisfies the condition,

14×14-6=196-6=190

which is divisble by 19.

Go to Question:

Prev Question

Next Question