AP ICET 2016 Paper

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Question : 85 of 200

Marks: +1, -0

If

a+b=7,b+c=-3,c+a=-4

then

a^{3}+b^{3}+c^{3}=

252
-252
1
0

Solution:

Given :

a+b=7,b+c=-3,c+a=-4

(a+b)+(b+c)+(c+a)=7–3–4=0

⇒2(a+b+c)=0

⇒a+b+c=0

∴a=(a+b+c)–(b+c)=3

Similarly,

b=4,c=–7

a^3+b^3+c^3=3abc[a+b+c=0]

=3(3)(4)(–7)=-252

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