If 2^{2n-1}= \frac{1}{8^{n-3}},then 2^{n-2}

AP ICET 2016 Paper

Question : 83 of 200

Marks: +1, -0

2^{2n-1}=\;\;{1}/{8^{n-3}}

,then

2^{n-2}

Solution:

Given :

2^{2n-1}={1}/{8^{n-3}}

2^{2n-1}={1}/{2^{3(n-3)}}={1}/{2^{3n-9}}=2^{9-3n}

⇒2n-1=9-3n

⇒5n=10

⇒n=2

∴2^{n-2}=2^{2-2}=2^{0}=1

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