AP ICET 2015 Paper

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Question : 41 of 200

Marks: +1, -0

\;\;{5}/{3},\;\;{29}/{6},

_______

\;\;{131}/{12},\;\;{179}/{15}

$59/9$
$71/9$
$89/9$
$91/9$

Solution:

\;\;{5}/{3},\;\;{29}/{6},

___

\;\;{131}/{12},\;\;{179}/{15}

The denominators of consecutive terms increase by 3.

{(3×2)-1}/{3},{(6×5)-1}/{6},{?}/{9},{(12×11)-1}/{12},{(15×14)-1}/{15}

∴?=9×8–1=71

∴ The missing term is

71/9

Note : The last term should be

209/15

in place of

179/15

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