AP ICET 2015 Paper

Question : 148 of 200

Marks: +1, -0

When two unbiased dice are thrown at random, then the probability that the sum on them is an odd prime number is

Solution:

Total no. of possible outcomes

=6×6=36

Favourable outcomes that the sum is an odd prime :

\{\table (1,2)\,(2,1)\,(1,4)\,(4,1)\,(2,3)\,(3,2)\,;(1,6)\,(6,1)(2,5)\,(5,2)\,(3,4)\,;(4,3)\,(5,6)\,(6,5)\}.

No. of favourable outcomes = 14
Required probability

=14/36=7/18

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