AP ICET 2015 Paper

Question : 128 of 200

Marks: +1, -0

The sum of the first 10 terms of the progression 2, 5, 8, 11, .... is

Solution:

2, 5, 8, 11, .........
It is an A.P. whose first term, a = 2 and common difference, d = 3

S_n=n/2[2a+(n-1)d]

∴S_10=10/2[2×2+9×3]=5×31=155

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