{1}/\sqrt{3}+\sqrt{2}=x\sqrt{2}+y\sqrt{3}\Rightarrowx-y=

AP ICET 2015 Paper

Question : 104 of 200

Marks: +1, -0

{1}/{√{3}+√{2}}=x√{2}+y√{3}⇒x-y=

Solution:

{1}/{√{3}+√{2}}=^{x}√{2}+^{y}√{3}

⇒{√{3}-√{2}}/{(√{3})^{2}-(√{2})^{2}}=^{x}√{2}+^{y}√{3}

⇒√{3}-√{2}=x√{2}+y√{3}

⇒x=-1,y=1

∴x-y=(-1)-(1)=-2

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