If x=(\frac{a+b}{a-b}), y=(\frac{b+c}{b-c}), z=(\frac{a+c}{c-a}) and a \\neqb \\neqc then (\frac{1-x}{1+x})(\frac{1-y}{1+y})(\frac{1-z}{1+z})=

AP ICET 17 Sep 2021 Shift 2 Paper

Question : 147 of 200

Marks: +1, -0

x=({a+b}/{a-b}), y=({b+c}/{b-c}), z=({a+c}/{c-a})

and

a \≠b \≠c

then

({1-x}/{1+x})({1-y}/{1+y})({1-z}/{1+z})=

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